Mathematica Asked on April 14, 2021
https://mathematica.stackexchange.com/a/222410/73364
I have obtained the following code from the above link. But it is not working well with my situation. Can anyone help me out?
SumHeld /:
SyntaxInformation[
SumHeld] = {"LocalVariables" -> {"Table", {2, Infinity}}};
IndexUnify[HoldPattern@Plus[sums : SumHeld[_, __] ..]] :=
Plus @@ With[{targetIndices = List @@ #[[-1, 2 ;;, 1]],
sourceIndicesList = List @@@ #[[;; , 2 ;;, 1]]},
Function[{sum, sourceIndices},
sum /. Thread[
sourceIndices ->
Take[targetIndices, Length@sourceIndices]]] @@@
Transpose@{#, sourceIndicesList}] &@
SortBy[Flatten /@ {sums}, Length]
SumTogether[HoldPattern@Plus[sums : SumHeld[_, sameRanges__] ..]] :=
SumHeld[Plus @@ {sums}[[;; , 1]], sameRanges]
SumTogether[HoldPattern@Plus[sums : SumHeld[_, __] ..]] /;
UnsameQ @@ {sums}[[;; , 2 ;;]] :=
Plus @@ SumTogether@*Plus @@@ GatherBy[{sums}, Rest]
Here please see the below test case.
test = SumHeld[f[a, i], {a, 1, 5}, {i, 1, 5}] +
SumHeld[SumHeld[2*f[b, j], {b, 1, 5}], {j, 1, 5}] +
SumHeld[SumHeld[2*f[c, j], {c, 1, 5}], {j, 1, 5}]
% // IndexUnify
% // SumTogether
The output I am receiving is
$$text{SumTogether}left(sum _{c=1}^5 sum _{j=1}^5 f(c,j)+2 sum _{c=1}^5 sum _{j=1}^5 2 f(c,j)right)$$
Here the issue is it’s not simplifying further as $$left(sum _{c=1}^5 sum _{j=1}^55f(c,j)right)$$
Another question is when I have more than 2 summation signs as below:
test = SumHeld[f[a, i, j], {a, 1, 5}, {i, 1, 5}, {j, 1, 5}] +
SumHeld[SumHeld[2*f[b, j, i], {b, 1, 5}, {j, 1, 5}], {i, 1, 5}] +
SumHeld[SumHeld[2*f[c, j, i], {c, 1, 5}, {j, 1, 5}], {i, 1, 5}]
% // IndexUnify
% // SumTogether
Is the bracket I have placed correctly?
If you observe the definition of SumTogether
carefully, you'll find it only works on SumHeld[…]
with no coefficient. So we need to define a rule for SumHeld[…]
with coefficient:
SumHeld /: c_?NumericQ SumHeld[rest_, range__] := SumHeld[c rest, range]
Correct answer by xzczd on April 14, 2021
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