Derivative of predictor function

Question

Given some data dat, we would like to generate a predictor function. Therefore we use
 pdata = Map[#[[1]] -> #[[2]] &, dat];
 p = Predict[pdata, Method -> "NeuralNetwork", PerformanceGoal -> "Quality"];

If one tries to take the derivative of p[x] via (here as an example at 2.)
 ND[p[x], x, 2.]

Mathematica returns PredictorFunction::bfttype: "Invalid argument x. feature1 is a Numerical feature. How can one perform a derivation of the PredictorFunction?

pawel_winzig · Answer

I found it: It is the same case as with the integration of compiled functions. One has to use a wrapper:
foo[x_?NumericQ] := p[x];
The function foo can now be differentiated using ND.

Derivative of predictor function

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