Mathematica Asked by Bruna Mendonça on February 19, 2021
I am trying to solve a 2nd order ODE to reproduce a plot.
Here are the equations:
dline1[n_, γ_, α_,
Vz_, μ_, η_, Δ_,
r] = -η (D[y[r], r] + 1/r*D[uup[r], r]) + (Vz - μ)*
uup[r] + α*(1/r*udown[r] +
D[udown[r], r]) - Δ*Exp[I*γ]*udown[r];
dline2[n_, γ_, α_,
Vz_, μ_, η_, Δ_,
r] = -α*(D[uup[r], r]) + Δ*Exp[-I*γ]*
uup[r] - η (z'[r] +
1/r*D[udown[r], r] - (n + 1)^2/(4 r^2)*
udown[r]) + (-Vz - μ)*udown[r];
It works okay for Delta=0 and solving analytically:
solin1 = dline1[1, 0, 1, 1, 0, 1, 0, r] /. {uup[r] -> BesselJ[0, z*r],
D[uup[r], r] -> D[BesselJ[0, z*r], r],
y'[r] -> D[BesselJ[0, z*r], {r, 2}], udown[r] -> BesselJ[1, z*r],
D[udown[r], r] -> D[BesselJ[1, z*r], r],
z'[r] -> D[BesselJ[1, z*r], r]};
solin2 = dline2[1, 0, 1, 1, 0, 1, 0, r] /. {uup[r] -> BesselJ[0, z*r],
But it does not work for nonzero Delta and NDSolve, since it deverges to +infinity for one solution and -infinity for other.
I tried to make it uncoupled to see what is going on (alpha=Delta=0). The Second equation is Bessel-like, as expected:
soluncoupled2 =
NDSolve[{dline2[1, 0, 0, 1, 0, 1, 0, r] == 0,
z[r] == D[udown[r], r], z[ϵ] == 0.5,
udown[ϵ] == 0},
{udown}, {r, 40}, Method ->
"Automatic"}
] // Flatten;
Plot[Evaluate[{udown[r]} /. soluncoupled2], {r, 0, 40},
PlotRange -> Automatic,
PlotLegends -> {"!(*SubscriptBox[(u), (↓)])"}]
but the first one is not!
soluncoupled1 =
NDSolve[{dline1[1, 0, 0, 1, 0, 1, 0, r] == 0, y[r] == D[uup[r], r],
y[ϵ] == 0,
uup[ϵ] == 1},
{uup}, {r, ϵ, 40}, MaxSteps -> Infinity,
Method -> {"Automatic"}] // Flatten;
Plot[Evaluate[{uup[r]} /. soluncoupled1], {r, 0, 40},
PlotRange -> Automatic,
PlotLegends -> {"!(*SubscriptBox[(u), (↑)])"}]
Any ideas? I tried many options for "Methods". Even making u[40]=v[40]=0 does not work. I also changed the boundaries, but still diverges.
soluncoupled1
can be obtained symbolically:
DSolveValue[{uup[r] - Derivative[1][uup][r]/r - uup''[r] == 0,
uup[0] == 1, uup'[0] == 0}, uup[r], r]
(* BesselJ[0, I r] *)
which is equivalent to BesselI[0, r]
:
FullSimplify[BesselJ[0, I r] == BesselI[0, r], r > 0]
(* True *)
Because BesselI[0, r]
diverges exponentially for large r
, it is not surprising that numerical solutions do the same.
Of course, it may be possible to find some set of parameters for which the coupled set of equations does not diverge. If so, numerical issues would be likely, because avoiding divergences probably would require precise numerical cancellation of some terms.
Correct answer by bbgodfrey on February 19, 2021
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