Mathematica Asked by enzotib on December 31, 2020
Reading this question on Math.SE, I tried the following Mathematica instructions
In[1]:= i1 = Integrate[1/Sqrt[1 + t^4], {t, 0, 1}];
i2 = Integrate[Sec[u]^2/Sqrt[1 + Tan[u]^4], {u, 0, [Pi]/4}];
FullSimplify[i1 == i2]
FullSimplify[i1 == i2] // N
Out[3]= Sqrt[[Pi]] EllipticK[1/2] == 4 Gamma[5/4]^2
Out[4]= True
so, given that the two integrals are the same, apart from a change of variable, I ask: why Mathematica does not know?
Use FunctionExpand
$Version
(* "12.1.1 for Mac OS X x86 (64-bit) (June 19, 2020)" *)
Clear["Global`*"]
i1 = Integrate[1/Sqrt[1 + t^4], {t, 0, 1}]
(* (2 Gamma[5/4]^2)/Sqrt[π] *)
i2 = Integrate[Sec[u]^2/Sqrt[1 + Tan[u]^4], {u, 0, π/4}]
(* 1/2 EllipticK[1/2] *)
i1 == i2 // FunctionExpand // FullSimplify
(* True *)
Correct answer by Bob Hanlon on December 31, 2020
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