Mathematica Asked on April 9, 2021
I need to display two y-values for a list of points. I tried doing this:
data=Import["https://pastebin.com/raw/cJtpDmcm","Table"];
p1=ListPlot[data[[All,1;;2]],PlotRange->{{6,10},{3,7}},ImageSize->500,PlotTheme->"Monochrome",BaseStyle->Directive["TR",FontSize->16,Black],Frame->{{True,False},{True,True}},FrameTicks -> {{All, None}, {All,None}},ImagePadding ->{{60, 60}, {60,10}}];
p2=ListPlot[data[[All,3;;4]],PlotRange->{{6,10},{100,300}},PlotTheme->"Monochrome",ImageSize->500,BaseStyle->Directive["TR",FontSize->16,Black],Frame->{{False,True},{False,False}},FrameTicks -> {{None, All}, {None, None}},ImagePadding ->{{60, 60}, {60,10}},FrameStyle -> {{Automatic, Red}, {Automatic, Automatic}},FrameTicksStyle -> Directive[16, "TR"],PlotStyle->Red];
Overlay[{p1,p2}]
Output:
It works, but I wish I could rescale the red y-values so I only need to plot one set of dots. Something like this:
How can I do that?
The tick marks on the right can constructed with an interpolation function like this:
data = Import["https://pastebin.com/raw/cJtpDmcm", "Table"];
ifun42 = Interpolation[data[[All, {4, 2}]], InterpolationOrder -> 1];
labels = {150, 200, 250, 300, 350};
ticks = Table[{ifun42[x],
If[TrueQ@MemberQ[labels, x], Style[x, Red], Null]},
{x, 100, 350, 10}] // Quiet;
The interpolation is from the 4th column of data to the 2nd. Note that an interpolation order of 1 spaces the tick marks linearly between the data points, not between the tick labels. This effect can be seen by comparing the spacing of the ticks at 160 and 170 to the spacing of the ticks at 170 and 180. A higher order interpolation, like the default of 3, gives better results.
For the horizontal and vertical gridlines, we will just use the Epilog
option. But first, we construct the lines like this
pRange = {{6, 11}, {3, 8}};
horzLines = {Thin, Dashed,
Red, Line[Table[
{pt, {pRange[[1, 2]], pt[[2]]}}, {pt, data[[All, {1, 2}]]}]],
Blue, Line[Table[
{{pRange[[1, 1]], pt[[2]]}, pt}, {pt, data[[All, {1, 2}]]}]]};
vertLines = {Thin, Dashed, Black, Line[Table[
{pt, {pt[[1]], pRange[[2, 1]]}}, {pt, data[[All, {1, 2}]]}]]};
Now pull it all together like this
ListPlot[data[[All, 1 ;; 2]],
PlotRange -> pRange,
Frame -> True,
FrameTicks -> {{All, ticks}, {All, None}},
Epilog -> {horzLines, vertLines}
]
Correct answer by LouisB on April 9, 2021
Adapting Jason B.'s answer here
Still plots two sets of points though.
TwoAxisListPlot[{list1_, list2_}, opts : OptionsPattern[]] :=
Module[{plot1, plot2, ranges},
{plot1, plot2} = ListLinePlot /@ {list1, list2};
ranges = Last@Charting`get2DPlotRange@# & /@ {plot1, plot2};
ranges[[2]] = Reverse@Last@ranges;
ListPlot[{list1, Transpose[{
First /@ list2,
Rescale[Last /@ list2, Last@ranges, First@ranges]}]},
Frame -> True,
FrameTicks -> {
{Automatic, Charting`FindTicks[First@ranges, Last@ranges]},
{Automatic, Automatic}},
FrameStyle -> {{Automatic, ColorData[97][2]}, {Automatic, Automatic}},
FilterRules[{opts}, Options[ListPlot]]]]
data = Import["https://pastebin.com/raw/cJtpDmcm", "Table"];
TwoAxisListPlot[{data[[All, {1, 2}]], data[[All, {3, 4}]]}, Joined -> False]
Answered by Chris Degnen on April 9, 2021
Using ifun42
from LouisB's answer in an alternative way
ifun42 = Interpolation[data[[All, {4, 2}]], InterpolationOrder -> 1];
invifun42 = InverseFunction @ ifun42;
options = {BaseStyle -> Directive["TR", FontSize -> 16, Black],
PlotStyle -> Black, ImageSize -> 500, PlotRange -> All,
PlotRangePadding -> 1, Frame -> True,
FrameStyle -> {{Automatic, Red}, {Automatic, Automatic}},
FrameTicks -> {{All, Charting`ScaledTicks[{ifun42, invifun42}][##, {6, 2}] &},
{All, None}},
GridLines -> Automatic, GridLinesStyle -> Dashed};
ListPlot[{MapAt[ifun42, data[[All, 3 ;; 4]], {All, 2}], data[[All, 1 ;; 2]]},
PlotStyle -> {Directive[Red, AbsolutePointSize[15]], Black}, options]
Alternatively,
prolog = ListPlot[data[[All, {3, 4}]],
ScalingFunctions -> {None, {ifun42, invifun42}},
PlotStyle -> Directive[Red, AbsolutePointSize[15]]][[1]];
ListPlot[data[[All, 1 ;; 2]], options, Prolog -> prolog]
same picture
Replace {6, 2}
in Charting`ScaledTicks[...][...]
with {10, 1}
to get
Answered by kglr on April 9, 2021
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