Mathematica Asked on July 4, 2021
SyntaxInformation[f] = {"ArgumentsPattern" -> {}};
f[] := 0;
After one ClearAll[f]
or ClearAll["`*"]
, f
remains black. It takes two to turn f
blue, and it can’t be in the same cell: just running ClearAll[f];ClearAll[f]
is not enough. Yet one ClearAll
is enough to clear FullDefinition[f]
.
In fact, the line f[] := 0;
is extraneous; all that’s needed is to define SyntaxInformation[f]
.
Is this a bug? Is there anything I can run once to turn everything blue?
It's a bug. From Wolfram Technical Support: "I have reproduced the issue and have reported it to our developers."
Workaround, from the comments by Lukas Lang: SyntaxInformation[f]=.; ClearAll[f]
or Quiet[Unset@*SyntaxInformation@*Symbol /@ Names["`*"]]; ClearAll["`*"]
.
Correct answer by Blrp on July 4, 2021
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