Mathematica Asked on June 10, 2021
When I execute f[g[a, b]] /. f[g[l__]] :> f[l] I get f[a, b] as expected.
When I execute f[a + b] /. f[Plus[l__]] :> f[l] I get f[a + b]. (I expect f[a, b] again)
Why?
(Wolfram Mathematica 12.2.0)
This happens because Plus[l__] evaluates to l__ before the pattern is even replaced. Try instead:
f[a + b] /. f[HoldPattern@Plus[l__]] :> f[l]
Answered by Fidel I. Schaposnik on June 10, 2021
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