Geographic Information Systems Asked on August 2, 2021
I would like to check if my set of NDVI images with min/max values from -1 +1 is good for at least 80%.
I took my cue from this other topic: here. Considering that the nodata is -32768
But the values I get on multiple images are all the same.
with rasterio.open(NDVI[0], 'r') as src:
meta = src.meta.copy()
meta.update({"nodata":-32768})
data = src.read(1)
arr=data[data>-1.0]
pct_valid = 100 * (arr != meta['nodata']).sum() / (meta['width'] * meta['height'])
print('%.4f'%pct_valid)
OUTPUT:
-6.87526
How should I interpret it for my image?
To select only those images that are 80% good instead?
if pct_valid > 80.0:
write(raster)
Here is an option that uses numpy
to check if NoData values account for >20% of the total pixels.
The code is designed to be included in a for
loop while iterating through a directory of images. If the routine detects an image that meets the 80% threshold, it returns a True
, else False
. Otherwise it would be easy to convert the function to populate a list of valid images.
import os
import rasterio
import numpy as np
img = '/path/to/geotiff.tif'
nodata_value = -32768 # enter the NoData value here
def check_image(img, nodata_value):
# Read in image as a numpy array
src = rasterio.open(img).read(1)
# Count the occurance of NoData values in np array
nodata_count = np.count_nonzero(array == nodata_value)
# Get a total pixel count
total_count = array.shape[0] * array.shape[1]
# Get a % of NoData pixels
val = nodata_count/total_count * 100
# Check if image meets threshold of 80% valid pixels
if val < 20:
print("Image {0} has >= 80% of pixels that are valid".format(os.path.basename(img)))
return True
else:
print("Image {0} has <80% of pixels that are valid".format(os.path.basename(img)))
return False
if __name__ == "__main__":
check_image(img, nodata_value)
Correct answer by Aaron on August 2, 2021
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