Identifying coordinate format from exif data

Question

I am using the Python exif module to extract coordinates from photos. The methods for doing so are: gps_latitude and gps_longitude.
The output for latitude is: (32.0, 37.0, 37.15) and longitude is: (116.0, 30.0, 37.0)

I extracted the location using another tool as well:

32°37'37.2"N 116°30'37.0"W and 32.6270000, -116.5102778

How can I identify the output format: (32.0, 37.0, 37.15), (116.0, 30.0, 37.0) so I can covert it to perhaps decimal degrees?
from exif import Image

with open('IMG_0252.jpg', 'rb') as image_file:
    my_image = Image(image_file)
    print(my_image.gps_latitude, my_image.gps_longitude)

user2856 · Accepted Answer

They are in degrees, minutes, seconds (DMS) format.
To convert to decimal degrees, the basic formula is:
degrees + minutes / 60 + seconds / 3600

Note that 'W' longitudes and 'S' latitudes are negative, so you need to use the gps_latitude_ref and gps_longitude_ref properties to determine that.  Here's a worked example:
from exif import Image

def dms_to_dd(gps_coords, gps_coords_ref):
    d, m, s =  gps_coords
    dd = d + m / 60 + s / 3600
    if gps_coords_ref.upper() in ('S', 'W'):
        return -dd
    elif gps_coords_ref.upper() in ('N', 'E'):
        return dd
    else:
        raise RuntimeError('Incorrect gps_coords_ref {}'.format(gps_coords_ref))

with open('IMG_0252.jpg', 'rb') as image_file:
    my_image = Image(image_file)

# gps_latitude = (32.0, 37.0, 37.15)
    # gps_longitude = (116.0, 30.0, 37.0)
    # 
    # gps_latitude_ref = 'N'
    # gps_longitude_ref = 'W'
    
    print(dms_to_dd(my_image.gps_latitude, my_image.gps_latitude_ref))
    print(dms_to_dd(my_image.gps_longitude, my_image.gps_longitude_ref))

32.62699
    -116.51028

Identifying coordinate format from exif data

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