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Getting path of project, or layer file in PyQGIS?

Geographic Information Systems Asked by fccoelho on January 19, 2021

I am generating new raster files from vector layers on a project. I would like to save them in the same directory as the project or layer files.

How do I find this path using PyQGIS?

5 Answers

For python console:

QgsProject.instance().readPath("./") # also try "../"

Or with

dir(QgsProject.instance())

you find something like

fileName()

For python plugin (not tested!):

from PyQt4.QtGui import QMessageBox
from qgis.core import QgsProject
path_absolute = QgsProject.instance().readPath("./")
QMessageBox.information(None, "Title", "AP: " + unicode(path_absolute))

Correct answer by qräbnö on January 19, 2021

If you want to access a vector file path, on a active layer, this seems to work:

myfilepath= os.path.dirname( unicode( qgis.utils.iface.activeLayer().dataProvider().dataSourceUri() ) ) ;
fic = myfilepath + "[% "FILE" %]"

then to open a picture or text located in same directory as mylayer:

from PyQt4 import QtWebKit, QtCore ; vue=QtWebKit.QWebView() vue.setUrl( QtCore.QUrl( fic ) ) ; vue.show()

Answered by rha on January 19, 2021

To access a vector file path, on a active layer, this code works well in Python Console:

>>>import os
>>>myfilepath= iface.activeLayer().dataProvider().dataSourceUri()
>>>myfilepath
u'/home/zeito/tiznados_canoa.tif'
>>>(myDirectory,nameFile) = os.path.split(myfilepath)
>>>myDirectory
u'/home/zeito'
>>>nameFile
u'tiznados_canoa.tif'

It was tested with my 'tiznados_canoa.tif' raster as a active layer.

Answered by xunilk on January 19, 2021

I did test this on QGIS 3.4
QgsProject.instance().fileName()

will return the entire path to the file

'C:/MyDirectory/18809_US66.qgz'

Answered by Cary H on January 19, 2021

In QGIS 2.x, 3.0 and 3.1:

Project path:

QgsProject.instance().fileName()  # C:/test/sample_project.qgs

Project folder path:

QgsProject.instance().homePath() # C:/test

In QGIS 3.2+:

Project path:

QgsProject.instance().fileName() 
# OR
QgsProject.instance().absoluteFilePath() # C:/test/sample_project.qgz 

Project folder path:

QgsProject.instance().homePath()
# OR
QgsProject.instance().absolutePath()   # C:/test

Answered by Kadir Şahbaz on January 19, 2021

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