TransWikia.com

Why am I getting wrong value here?

Engineering Asked by Srijan M.T on June 12, 2021

A man threw a ball with force 10 N to two displacement of 5 m and 10 m.

  • F = ma, so let mass be 2 kg.
  • a = 5 m/s2.

Work done = 10 × 5 and 10 × 10 = 50 Nm and 100 Nm.

Now, since a = 5, I assumed that after 5 m velocity = 25 [m/s].

Now, when I do K.E f – K.E initial for final work done i.e 50 Nm for now.

  • Initial K.E. = 0.

So , then K.E final is not equal to work done final.
25 × 25 is not equal to 50 Nm.

Where am I wrong?

One Answer

The mistake is in your assumption.

Now, since a = 5, I assumed that after 5 m velocity = 25 m/s.

the correct would have been

Now, since a = 5, I assumed that after 5 [s] velocity = 25 m/s.

The way you can calculate it is from the following form of the equation for acceleration:

$$a = u frac{du}{ds}$$

you can obtain that $acdot 5m = frac{u_{out}^2}{2} rightarrow u_{out} = sqrt{2 cdot acdot 5[m]}$.

The rest I leave to you.

Correct answer by NMech on June 12, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP