Torque based bending on shaft

Yes the force will have at B a torque of

T= -30* 0.8= -24kN.m

And BO will act as a cantilever beam under 30kN upward load. The moment upward at 0 will be:

M= 30kN * 1.2 =36kN.m upward.

Assuming up as positive sign fo force.

So the BO will both twist clockwise and bend upwards. Below is an exaggerated sketch of the deflected bar.

This is a riff on @kamran's answer, but I hope it's different enough to be worthwhile.

Look at the arm AB, and the action of the upward force. Now do the statics around just the arm -- you'll find that at point B, there is an upward force and a moment.

As long as the deflection in the member from B to O is small enough, and nothing hits its elastic limit or just plane breaks, you can separately calculate the effect of the torque from the effect of the upward force. When you're done, you can add those effects together for a final answer.