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the volume in hydraulic retention time is of reactor/container or liquid

Engineering Asked on November 18, 2020

I have a tiny reactor, and the volume I need is 425ml. If there is no/few other reactants, then the volume in hydraulic retention time is clear: reactor/container’s volume. and hrt is V/u(V is 425ml, u is flow rate) But if I fill 80% of container with something like lime mud, the real volume of water is only 20% left — 85ml. How is my V should be? 425 or 85ml? IOW, the volume in hydraulic retention time is of reactor/container or liquid?

One Answer

Water volume is 85 ml now, so the hrt is 85 ml/u. The liquid retention time because the mud doesn't react, right?

Answered by user20096 on November 18, 2020

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