TransWikia.com

Force required to deform sheet metal

Engineering Asked by Stefan Foot on January 19, 2021

enter image description here

Hi all. I am building a machine to deform sheet metal into corrugations. I have attached an image that I got off a presentation from MIT’s website. In the example, they provide a formula for the creation of a single indentation.

I edited the image to give you an idea of the shape I am going for. It is essentially a “W” shape after pressing.

I do not know how to apply the formula to my design. Is it the same amount of force that I would require? Double the force or even triple the force. My gut feel is that it should be somewhere between the same and double the force.

Any help would be appreciated.

Kind regards
Stefan

One Answer

The plastic section modulus for the plate is

$S = frac {bh^2}{6} = frac {LT^2}{6} $

W defines the narrowness of the grove, the narrower W, the bigger F is required.

I your case because you have two groves next to each other with no flat band in between there is tension in the two groves by the lateral dragging of the sheet into the jig.

If we were to estimate force needed to bend only the two indentations it would be just 2F. But because there is some extra force spent on dragging the sheet up the inclined walls of the center ridge, it's sate to allow 2.5 F.

Answered by kamran on January 19, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP