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Frequency response of BJT frequencies with CE bypassed

Electrical Engineering Asked on December 31, 2021

In a lot of reference I see divergence like Zce = RE || (beta re + Rb || Rs) / (beta + 1) etc.
$$Z_{ce} = R_E || left(frac{beta.r_e + R_b || R_s}{beta + 1}right)$$

See link 1, link 2, link 3, link 4

but from a trivial example I get

Zce = RE || (beta re + Rb || Rs) / (beta)
$$Z_{ce} = R_E || left(frac{beta .r_e + R_b || R_s}{beta}right)$$

Frequency response of BJT frequencies with CE bypassed

Note : with that, i get the same result than here with the result of Electronic Devices and Circuit Theory, by Boylestad and Nashelsky.

Note : I know with beta >= 100 it is the same but i like to have a rigourous demonstration.

Do you think it is a good reasoning here ?

One Answer

Solution:

  1. The error done is that it is necessary to include all the branches of the current sources (ic was forgotten).
  2. Another error is that since

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to get

enter image description here

a bad representation of the current branches which does not respect the transistor (with its currents ie, ic, ib) gives an unusable diagram

enter image description here

[fig. 1] is the good choice.

[fig. 2] it makes no sense.

So the solution is [fig. 1] and you get

enter image description here

thus the calculation of z1 gives

enter image description here

and finally you can give this representation

enter image description here

and for the calculation of Z you do not have to worry about the current flowing in Re nor in Z1.


Likewise, you must remember of considering the BJT with its current on its ports (ie, ib, ic) so make the extensions of the wires with their currents.

  • Case of a good calculation from RE : put the pen between RE and ie : you'll see it's RE || Z1. In this case, you can calculate Z1 with the branch ib, ic :

enter image description here

  • Case of a bad calculation of Z1 :

enter image description here

Likewise, the BJT with its current on its ports (ie, ib, ic) so make the extensions of the wires with their currents. In theses pictures you'll see a demonstration with $ r_e $ and $ pi $ model.

Demonstration with $ r_e $ (or T) model : re model

Demonstration with $ pi $ model ($ pi $ model obtained with the T model) : pi model

Answered by user7058377 on December 31, 2021

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