Electrical Engineering Asked on December 31, 2021
In a lot of reference I see divergence like Zce = RE || (beta re + Rb || Rs) / (beta + 1) etc.
$$Z_{ce} = R_E || left(frac{beta.r_e + R_b || R_s}{beta + 1}right)$$
See link 1, link 2, link 3, link 4
but from a trivial example I get
Zce = RE || (beta re + Rb || Rs) / (beta)
$$Z_{ce} = R_E || left(frac{beta .r_e + R_b || R_s}{beta}right)$$
Note : with that, i get the same result than here with the result of Electronic Devices and Circuit Theory, by Boylestad and Nashelsky.
Note : I know with beta >= 100 it is the same but i like to have a rigourous demonstration.
Do you think it is a good reasoning here ?
Solution:
to get
a bad representation of the current branches which does not respect the transistor (with its currents ie, ic, ib) gives an unusable diagram
[fig. 1] is the good choice.
[fig. 2] it makes no sense.
So the solution is [fig. 1] and you get
thus the calculation of z1 gives
and finally you can give this representation
and for the calculation of Z you do not have to worry about the current flowing in Re nor in Z1.
Likewise, you must remember of considering the BJT with its current on its ports (ie, ib, ic) so make the extensions of the wires with their currents.
Likewise, the BJT with its current on its ports (ie, ib, ic) so make the extensions of the wires with their currents. In theses pictures you'll see a demonstration with $ r_e $ and $ pi $ model.
Demonstration with $ r_e $ (or T) model :
Demonstration with $ pi $ model ($ pi $ model obtained with the T model) :
Answered by user7058377 on December 31, 2021
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