Database Administrators Asked on November 11, 2021
I have a table with this data:
shyam banarjee
rahul khanna
priya kumari
rohit srivastava
I just want first names, like this:
shyam
rahul
priya
rohit
This will allow you to choose which part by simply filtering on RowNum. It will work no matter how many values you have...(assuming data is in a table called #temp)
SELECT
FIELD1,Value,ROW_NUMBER() OVER(PARTITION BY FIELD1 ORDER BY FIELD1) RowNum
FROM
#Temp T
CROSS APPLY STRING_SPLIT(FIELD1, ' ') T1
Specifically, this query will give you the first names. If you want last name, change it to RowNum=2 on last line.
SELECT Value FROM
(
SELECT
FIELD1,
Value,
ROW_NUMBER() OVER(PARTITION BY FIELD1 ORDER BY FIELD1) RowNum
FROM
#Temp T
CROSS APPLY STRING_SPLIT(FIELD1, ' ') T1
)
a
WHERE RowNum=1
Answered by Doug B on November 11, 2021
In Postgres you can use split_part()
split_part(the_column, ' ', 1);
Or, if you need to deal with multiple spaces, you can use regexp_split_to_array()
(regexp_split_to_array(the_column, 's+'))[1]
Answered by a_horse_with_no_name on November 11, 2021
You can use "Substrig" and "charindex" functions to get what you want.
See this code as a demo on how to use it:
declare @name varchar(30)
set @name = 'shyam banarjee'
select SUBSTRING(@name,1,charindex(' ',@name)-1)
In your case, instead of being a variable in the select, it will be your column name.
You could also look at "computed column" if ever you want to have a new column that would only contains the firstname.
Answered by Dominique Boucher on November 11, 2021
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