Database Administrators Asked by Gandalf StormCrow on February 18, 2021
I know that the order of returned rows is not guaranteed with the IN
statement in Postgres. For example if I do this:
SELECT users.id FROM users WHERE users.id IN (13589, 16674, 13588)
I may get this result:
16674
13588
13589
However, I want returned rows to respect the order in the IN
list, so I found few solutions online, such as:
SELECT users.id FROM users WHERE users.id IN (13589, 16674, 13588)
ORDER BY POSITION(id::text in '(13589, 16674, 13588)')
or
SELECT users.id FROM users WHERE users.id IN (13589, 16674, 13588)
ORDER BY id = 13589 desc,
id = 16674 desc,
id = 13588 desc;
I wonder if there is a nicer way to do this, or better yet more efficient?
WITH ORDINALITY
in Postgres 9.4+Introduced with Postgres 9.4. The manual:
When a function in the
FROM
clause is suffixed byWITH ORDINALITY,
abigint
column is appended to the output which starts from 1 and increments by 1 for each row of the function's output. This is most useful in the case of set returning functions such asunnest()
.
SELECT u.*
FROM unnest('{13589, 16674, 13588}'::int[]) WITH ORDINALITY AS x(id, order_nr)
JOIN users u USING (id)
ORDER BY x.order_nr;
x IN (set)
statements are rewritten internally in Postgres to x = ANY (array)
, which is equivalent:
SELECT users.id FROM users WHERE users.id = ANY ('{13589, 16674, 13588}')
You can see for yourself with EXPLAIN
.
For now, to preserve the order of elements, you could:
SELECT u.*
FROM (
SELECT arr, generate_subscripts(arr, 1) AS order_nr
FROM (SELECT '{13589, 16674, 13588}'::int[]) t(arr)
) x
JOIN users u ON u.id = x.arr[x.order_nr]
ORDER BY x.order_nr;
db<>fiddle here
Further reading:
Correct answer by Erwin Brandstetter on February 18, 2021
If you want to rewrite the condition slightly you could do something like this:
with id_list (id, sort_order) as (
values
(13589, 1),
(16674, 2),
(13588, 3)
)
select u.id
from users u
join id_list il on il.id = u.id
order by il.sort_order;
You can also put the values
clause directly into the join:
select u.id
from users u
join (
values
(13589, 1),
(16674, 2),
(13588, 3)
) as il(id, sort_order) on il.id = u.id
order by il.sort_order;
Answered by a_horse_with_no_name on February 18, 2021
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