Cross Validated Asked on December 27, 2021
Just wanted to ask whether the following derivation is correct:
Suppose $X$ is a vector of observed random variables, $Z$ is a vector of unobserved random variables and $theta$ is a vector of parameters. Let $S$ be the set of values $Z$ could take on; we’ll assume this is discrete. We’ll also assume the following are known
$f(x|z,theta)$ = the probability density function of X given Z and theta
$P(Z=z|theta)$ = the probability that $Z=z$ given $theta$
The likelihood function I want is
$prod_{zin S}[f(x|z,theta)P(Z=z|theta)]^{1_{Z=z}}$
Taking the logarithm:
$sum_{zin S}1_{Z=z}[log f(x|z,theta)+log P(Z=z|theta)]$
Now suppose I’m performing the EM algorithm and my current estimate of $theta$ is $theta^{(n)}$. Then I need to apply $E_{Z|theta^{(n)},x}$ to the above expression. This gives:
$sum_{zin S}P(Z=z|theta^{(n)})[log f(x|z,theta)+log P(Z=z|theta)]$
That is the expression I need to maximize with respect to $theta$ in the M step.
Is that correct, or did I make a mistake somethere? Thanks
Yes, your derivation looks correct. Just a minor clarification in the final expression -
In the expression, $sum_{zin S}P(Z=z|x,theta^{(n)})[log f(|z,theta)+log P(Z=z|theta)]$, the term $P(Z=z|x,theta^{(n)})$ would be computed in Expectation step; hence, during the maximization step, it is treated as constant value. In the M-step, derivatives are computed for only the terms within the bracket.
Answered by honeybadger on December 27, 2021
Get help from others!
Recent Questions
Recent Answers
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP