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In "advanced organic chemistry part A" book page:306&307 , the author uses the term 'solvent shell collapse' when talking about the reason for retention of conformation in tertiary benzyl...
Asked on 10/05/2021
0 answerSo let's say for a given molecule I have the volume of a unit cell, the shape of the unit cell (monoclinic, cubic, etc), the cell angles alpha, beta, and...
Asked on 10/05/2021 by crystallography
3 answerA couple of proofs from Chapter 2 of "Space Groups for Solid State Scientists" are giving me a hard time (see attached image). ...
Asked on 10/05/2021 by Nimanyu Joshi
1 answerIn an acid reaction with water, or other solvents, how do we know which atom(s) from a compound reacted with that solvent are the spectator ions? Are they the ones...
Asked on 03/08/2021 by Dixon
1 answerIn the following table from the CRC Handbook, molar conductivities of aqueous electrolytes are given for concentrations from infinite dilution to 0.1 M. However, I am...
Asked on 03/02/2021
0 answerI'm having a bit of trouble with the latter questions of this problem. $pu{15.0 mL}$ of $pu{1.4 M}$ $ce{HCl}$ was mixed with $pu{1.00 g}$ of ...
Asked on 02/25/2021 by user29462
2 answerThe one I have in my textbook is this: Shouldn't the first trough at $3500$ to around ...
Asked on 02/20/2021 by Ollie
2 answerWhen trying to solve for a molecule's molecular orbitals, we start off with the total molecular hamiltonian. However, given the difficulty of solving the Schrödinger Equation for this complicated hamiltonian...
Asked on 02/18/2021 by James Bond
1 answerIt is well-known thatA salt with a higher lattice energy will not dissolve at all, because then $Delta_{text{sol}}H^ominus$ will be negative.So, the reaction should be endothermic, right? My question...
Asked on 02/17/2021 by ultralegend5385
1 answerCould someone please explain to me in layman's terms what probability density of finding an electron means, just as probability means chances of finding an electron. With due respect, please...
Asked on 02/15/2021 by Arti gaikwad
3 answerGet help from others!
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