Board & Card Games Asked on November 25, 2021
You start this game with 3 cards of your choice in hand.
Your opponent starts with 0 cards in their hand.
Both libraries do not contain any other useful cards.
What is the highest life total you can end your turn at?
Assume you start at 20 life points. Beyond that, the rules can follow any of the official two-player formats by Wizard of the Coast.
Extra Challenge: If you want a personal challenge (although this is not what I am looking for in the answers to this question), try to find the 4-card infinite-life combo that made me restrict the puzzle to 3 cards only.
This is a legacy/modern entry (i.e. doesn't use Black Lotus).
Reveal Providence to go to 26 life. Then exile Autochthon Wurm to cast Nourishing Shoal to gain 15 life.
The question clarifies that there are two players. If we relax that restriction, we can do better in cases where there are 4 or more players. Have 3 Chancellor of the Dross in your opening hand and reveal all three to steal 9 life per opponent.
The question specifies three cards for a reason. Allowing one more card lets you go infinite. The 4 cards are Black Lotus, Daru Spiritualist, Shuko, and Diamond Valley.
Use Black Lotus to Cast Daru Spiritualist and Shuko. Repeatedly equip Shuko to Daru Spiritualist, giving Daru Spiritualist +2 toughness each time, until has [arbitrarity high odd number] toughness. Play Diamond Valley and use it to sacrifice Daru Spiritualist to gain [arbitrarity high odd number] life.
Answered by Zags on November 25, 2021
Black Lotus x2
Beacon of immortality
Depends on the format how much life you gain. 20 on a default game for example or 40 in Commander for example
Answered by Ivo Beckers on November 25, 2021
The best I can manage is 32 life:
A second solution for 32 life:
Answered by Dysnomian on November 25, 2021
Black Lotus x 2, Auriok Salvagers, Stream of Life
Play the lotuses and crack them for white. Cast Salvagers, use the 2 leftover to return lotus.
Cast lotus, crack for white, return lotus -> repeat as much as you want to gain a white mana each loop.
Return lotus, crack for green mana, cast stream of life for x + arbitrarily large number .
Answered by user29682 on November 25, 2021
With just 2 cards, you can be at arbitrarily many life points.
The 2-card combo is Black Lotus and Game of Chaos. As long as both you and your opponent keep playing, the stakes increase indefinitely, and you can end the game whenever you win a flip.
Assuming both you and your opponent keep playing exactly until someone gets to zero life or below during Game of Chaos' resolution, you can go to 103 life with the 2 card combo, or 109 with 3 cards.
If you win (+1), lose (-2), lose (-4), win (+8), lose (-16), win (+32), win (+64), then you (and your opponent) will be at
At the start of the game, reveal Providence for another 6 life - this doesn't change the sequence of coinflips because your opponent would still fall to 1 life at the same point of the sequence.
Answered by Hackworth on November 25, 2021
I'm going to cheat a bit... because you didn't specifically state that this was a 2-player game only (though you did use the word "both"...)
Hand:
This gives you an unbounded 3n life, where n is the number of opponents you have in the game.
With only 2 cards, you can get 2n life using Syphon Soul instead.
Answered by GendoIkari on November 25, 2021
Here is my best solution (42 Life Points):
Answered by David Coffron on November 25, 2021
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