How does heat math works? Are heat exchangers additive or multiplicative or something else?

Question

I got my hands on a couple of Exchangers++ in the black market, each should reduce heat from my weapons by 20%, so 40% total.

However, in a field, my mech is overheating much more than I have expected.

I have done some reading around and some claim that exchangers are multiplicative, but the math does not work out for them either.

What is the math behind Battletech heat and heat exchangers?

Hong Ooi · Answer

Heat exchangers are multiplicative. If you have 2 ++exchangers (20% reduced heat each), your total heat output will be 0.8^2 = 64% of the original. Note that:

How BT rounds numbers may be wonky.
The heat bar isn't a very good indication of your mech's true efficiency. However, if you hover your mouse over it, the tooltip figures should be accurate.

How does heat math works? Are heat exchangers additive or multiplicative or something else?

One Answer

Add your own answers!

Ask a Question