Stack Overflow Asked by Jamie Dixon on December 26, 2020
I have an IEnumerable<T>
method that I’m using to find controls in a WebForms page.
The method is recursive and I’m having some problems returning the type I want when the yield return
is returnig the value of the recursive call.
My code looks as follows:
public static IEnumerable<Control> GetDeepControlsByType<T>(this Control control)
{
foreach(Control c in control.Controls)
{
if (c is T)
{
yield return c;
}
if(c.Controls.Count > 0)
{
yield return c.GetDeepControlsByType<T>();
}
}
}
This currently throws a "Cannot convert expression type" error. If however this method returns type IEnumerable<Object>
, the code builds, but the wrong type is returned in the output.
Is there a way of using yield return
whilst also using recursion?
Inside a method that returns IEnumerable<T>
, yield return
has to return T
, not an IEnumerable<T>
.
Replace
yield return c.GetDeepControlsByType<T>();
with:
foreach (var x in c.GetDeepControlsByType<T>())
{
yield return x;
}
Correct answer by Marcin Seredynski on December 26, 2020
While there are many good answers out there, I would still add that it is possible to use LINQ methods to accomplish the same thing, .
For instance, the original code of the OP could be rewritten as:
public static IEnumerable<Control>
GetDeepControlsByType<T>(this Control control)
{
return control.Controls.OfType<T>()
.Union(control.Controls.SelectMany(c => c.GetDeepControlsByType<T>()));
}
Answered by yoel halb on December 26, 2020
As Jon Skeet and Colonel Panic note in their answers, using yield return
in recursive methods may cause performance problems if the tree is very deep.
Here's a generic non-recursive extension method that performs a depth-first traversal of a sequence of trees:
public static IEnumerable<TSource> RecursiveSelect<TSource>(
this IEnumerable<TSource> source, Func<TSource, IEnumerable<TSource>> childSelector)
{
var stack = new Stack<IEnumerator<TSource>>();
var enumerator = source.GetEnumerator();
try
{
while (true)
{
if (enumerator.MoveNext())
{
TSource element = enumerator.Current;
yield return element;
stack.Push(enumerator);
enumerator = childSelector(element).GetEnumerator();
}
else if (stack.Count > 0)
{
enumerator.Dispose();
enumerator = stack.Pop();
}
else
{
yield break;
}
}
}
finally
{
enumerator.Dispose();
while (stack.Count > 0) // Clean up in case of an exception.
{
enumerator = stack.Pop();
enumerator.Dispose();
}
}
}
Unlike Eric Lippert's solution, RecursiveSelect works directly with enumerators so that it doesn't need to call Reverse (which buffers the entire sequence in memory).
Using RecursiveSelect, the OP's original method can be rewritten simply like this:
public static IEnumerable<Control> GetDeepControlsByType<T>(this Control control)
{
return control.Controls.RecursiveSelect(c => c.Controls).Where(c => c is T);
}
Answered by Michael Liu on December 26, 2020
Seredynski's syntax is correct, but you should be careful to avoid yield return
in recursive functions because it's a disaster for memory usage. See https://stackoverflow.com/a/3970171/284795 it scales explosively with depth (a similar function was using 10% of memory in my app).
A simple solution is to use one list and pass it with the recursion https://codereview.stackexchange.com/a/5651/754
/// <summary>
/// Append the descendents of tree to the given list.
/// </summary>
private void AppendDescendents(Tree tree, List<Tree> descendents)
{
foreach (var child in tree.Children)
{
descendents.Add(child);
AppendDescendents(child, descendents);
}
}
Alternatively you could use a stack and a while loop to eliminate recursive calls https://codereview.stackexchange.com/a/5661/754
Answered by Colonel Panic on December 26, 2020
Others provided you with the correct answer, but I don't think your case benefits from yielding.
Here's a snippet which achieves the same without yielding.
public static IEnumerable<Control> GetDeepControlsByType<T>(this Control control)
{
return control.Controls
.Where(c => c is T)
.Concat(control.Controls
.SelectMany(c =>c.GetDeepControlsByType<T>()));
}
Answered by tymtam on December 26, 2020
I think you have to yield return each of the controls in the enumerables.
public static IEnumerable<Control> GetDeepControlsByType<T>(this Control control)
{
foreach (Control c in control.Controls)
{
if (c is T)
{
yield return c;
}
if (c.Controls.Count > 0)
{
foreach (Control childControl in c.GetDeepControlsByType<T>())
{
yield return childControl;
}
}
}
}
Answered by Torbjörn Hansson on December 26, 2020
You need to return the items from the enumerator, not the enumerator itself, in your second yield return
public static IEnumerable<Control> GetDeepControlsByType<T>(this Control control)
{
foreach (Control c in control.Controls)
{
if (c is T)
{
yield return c;
}
if (c.Controls.Count > 0)
{
foreach (Control ctrl in c.GetDeepControlsByType<T>())
{
yield return ctrl;
}
}
}
}
Answered by Rob Levine on December 26, 2020
You need to yield each of the items yielded by the recursive call:
public static IEnumerable<Control> GetDeepControlsByType<T>(this Control control)
{
foreach(Control c in control.Controls)
{
if (c is T)
{
yield return c;
}
if(c.Controls.Count > 0)
{
foreach (Control control in c.GetDeepControlsByType<T>())
{
yield return control;
}
}
}
}
Note that there's a cost to recursing in this way - you'll end up creating a lot of iterators, which can create a performance issue if you have a really deep control tree. If you want to avoid that, you basically need to do the recursion yourself within the method, to make sure there's only one iterator (state machine) created. See this question for more details and a sample implementation - but this obviously adds a certain amount of complexity too.
Answered by Jon Skeet on December 26, 2020
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