How to pass array to funtion to use as range based for loop

since c++20, you can use std::span<T>

void func(std::span<int> values) {
    for(auto& i : values) {
        std::cout << i << std::endl;
    }
}
int main() {
    int* arr = new int[5]{0,1,2,3,4};
    func({arr,5});
}

You can use C++ std::array:

#include <array>
#include <iostream>

void sortArray(std::array<int, 5> &arr)
{

    int count0s{0},count1s{0},count2s{0};
     for (int n: arr)
     {

     }

}
int main()
{
    std::array<int, 5> arr;
    sortArray(arr);
  
    return 0;
}

Or C++ std::vector:

#include <iostream>
#include <vector>

void sortArray(std::vector<int> &arr)
{

    int count0s{0},count1s{0},count2s{0};
     for (int n: arr)
     {

     }

}
int main()
{
    std::vector<int> arr;
    sortArray(arr);
  
    return 0;
}

Use a template to avoid a fixed size and type in the function:

#include <array>
#include <iostream>

template<typename T>
void sortArray(T &arr)
{
    int count0s{0},count1s{0},count2s{0};
    for (int n: arr)
    {
    }
}
int main()
{
    // it works with C arrays
    int arr[5];
    sortArray(arr);
    std::array<int, 5> arr2;
    sortArray(arr2);
    std::array<double, 5> arr3;
    sortArray(arr3);
    std::vector<double> arr4;
    sortArray(arr4);

    return 0;
}

With C++20 you can

#include <array>
#include <iostream>

void sortArray(auto &arr)
{
    int count0s{0},count1s{0},count2s{0};
    for (int n: arr)
    {
    }
}
int main()
{
    int arr[5];
    sortArray(arr);
    std::array<int, 5> arr2;
    sortArray(arr2);
    std::array<double, 5> arr3;
    sortArray(arr3);
    std::vector<double> arr4;
    sortArray(arr4);

    return 0;
}

parameter int arr[/*N*/] is in fact a pointer, (you cannot pass C-array by value).

but you can pass it by reference (syntax might surprise):

template <std::size_t N>
void sortArray(int (&arr)[N])
{
    // ...
}