Stack Overflow Asked by good_shabes on November 18, 2021
I get two array as response from some server, the arrays can be with different lengths. and I want to build a table from this arrays.
For example the server response is
let a1=response.a1;
let a2=response.a2;
where
a1=['a','b','c'];
a2=['d','e']
so I want the table be like:
+------+------+
| Col1 | Col2 |
+------+------+
| a | d |
| b | e |
| c | |
+------+------+
and I need something like:
var rows=""
for(var i=0;i<a1.length;i++)
{
for(var j=0;j<a2.length;j++)
{
rows+='<tr>....</tr>'
}
}
$('#myTbody').html(rows);
I mentioned this on the answer above, and just wanted to post an example of how you can get around the need to compare the length of the arrays. :)
What you can do is merge the two arrays into another array (create a 2d array), and then use the length of this merged array to get the total columns.
Then using a nested for loop, we can loop over each of the arrays in the 2d array, and add it as a row value to the column.
I have posted a simple example of this below :)
let a1 = ['a','b','c'];
let a2 = ['d','e'];
// Create a 2d array
// will look like [['a','b',''c], ['d','e']];
let mergedArray = [a1 , a2];
for(let i = 0; i < mergedArray.length; i++) {
// You would create the Column Here
console.log(`Col${i}`);
for(let j = 0; j < mergedArray[i].length; j++) {
// And here is the row value.
console.log(mergedArray[i][j]);
}
}
Answered by Spangle on November 18, 2021
HTML CODE :
<table id="myTbody">
</table>
Javascript code
a1 = ['a', 'b', 'c'];
a2 = ['d', 'e'];
var maxLen = 0;
if (a1.length > a2.length) {
maxLen = a1.length;
} else {
maxLen = a2.length;
}
var tableHtml = '<tr><th>col1</th><th>col2</th></tr>'
for (var i = 0; i < maxLen; i++) {
tableHtml = tableHtml + '<tr>';
tableHtml = tableHtml + '<td>' + (i >= a1.length ? '' : a1[i]) + '</td>';
tableHtml = tableHtml + '<td>' + (i >= a2.length ? '' : a2[i]) + '</td>';
tableHtml = tableHtml + '</tr>';
}
$('#tabby').html(tableHtml);
Answered by Runtime Terror - BS on November 18, 2021
The tricky thing here is that 1 array can be longer than the other, so first of all:
I've added // 1.
// 2.
and // 3.
to help reference the explaination.
const a1 = ['a','b','c']
const a2 = ['d','e','f','g']
const maxArrayLength = Math.max(a1.length, a2.length) // 1.
const tbody = document.querySelector('tbody');
for (let i = 0; i < maxArrayLength; i++) { // 2.
const tr = tbody.insertRow(); // 2.
tr.insertCell().innerHTML = a1[i] ? a1[i] : '' // 3.
tr.insertCell().innerHTML = a2[i] ? a2[i] : '' // 3.
}
<table>
<thead>
<tr>
<th>Col1</th>
<th>Col2</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
Answered by camaulay on November 18, 2021
const a1 = ['100','50000','60000'];
const a2 = ['1111','22222222'];
const greaterLength = (a1.length >= a2.length) ? a1.length : a2.length;
let store = "";
for(var i=0 ; i < greaterLength ; i++){
let a1Value = (a1[i] != undefined) ? a1[i] : "";
let a2Value = (a2[i] != undefined) ? a2[i] : "";
store += `<tr> <td>${a1Value}</td> <td>${a2Value}</td></tr>`;
}
alert(store);
complete the table body.
Answered by kd patel on November 18, 2021
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