Quantum Computing Asked on July 27, 2020
This statement can be found in Vedral et al. 1997, eq. (1).
More precisely, given a bipartite state $rho_{AB}$, they claim that any operation on $rho_{AB}$ involving local operations plus classical communication can be written as
$$sum_k (A_kotimes B_k)rho_{AB}(A_k^daggerotimes B_k^dagger)tag A$$
for some operators $A_k, B_k$. This is a seminal result, used for example to prove the existence of bound entangled states.
I don’t have any problem with the previous statement they make about general local operations being writable as $Phi_{mathrm{LGM}}(rho)=sum_{ij}(A_iotimes B_j)rho(A_i^dagger otimes B_j^dagger)$, as any such $Phi_{mathrm{LGM}}$ should be by definition writable as composition/tensor product of two local operations: $Phi_{mathrm{LGM}}=Phi_AotimesPhi_B$, and then if $A_i$ and $B_j$ are the Kraus operators of $Phi_A$ and $Phi_B$ we get the result.
However, when we allow classical communication it seems less obvious what a generic operation should look like. The Kraus decomposition of such a map $Phi$ would a priori be written $Phi(rho_{AB})=sum_k A_k rho_{AB} A_k^dagger$ where $A_k$ acts nonlocally on $AB$, but then I’m not sure how to translate the LOCC condition into a constraint for $Phi$.
The form (A) above is known as a separable superoperator. The effect of any LOCC protocol can be described as a separable superoperator, or as a separable POVM with POVM elements $N_i = A_iotimes B_i$.
This can be seen as follows (adapted from this answer - I will focus on the POVM case, the superoperator is obtained by ignoring the final outcome of the POVM):
Denote the parties by Alice and Bob. Without loss of generality, we can start with an action of Alice. Alice's first measurement has POVM elements $A_{i_1}otimes I$. Alice then communicates her outcome $i_1$ to Bob. Bob's subsequent measurement has elements $Iotimes A^{i_1}_{i_2}$, where $i_2$ enumerates Bob's outcomes, and $A^{i_1}$ indicates that Bob's POVM can depend on Alice's outcome. The total POVM of both has then elements $$ N_{i_1,i_2}=A_{i_1}otimes B^{i_1}_{i_2} , $$ which is a separable POVM $N_i=A_iotimes B_i$ with double index $iequiv{i_1,i_2}$.
Clearly, this can be iterated to an arbitrary number of rounds, and generalized to an arbitrary number of parties, and will always have POVM elements of the form $N_i=otimes B_iotimes cdots$.
Conversely, not every separable POVM can be written as a LOCC POVM. A counterexample is given in Bennett et al., Quantum Nonlocality without Entanglement, Phys. Rev. A. 59, 1070 (1999).
Correct answer by Norbert Schuch on July 27, 2020
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP