Quantum Computing Asked on May 3, 2021
The QPE on IBM platform finds the eigenvalue of a unitary operator, i.e $$U|phirangle=e^{2pi itheta}|phirangle$$
and uses the rotation operators as $$U(theta)=begin{bmatrix}0 & 1
1 &e^{itheta}end{bmatrix}$$
My question is we can write $U|phirangle=e^{2pi itheta}|phirangle$ as $$U|phirangle=e^{2e itheta}|phirangle$$ where, since even then the magnitude of the eigenvalue remains same. Of course that would require more number of measurement qubits. For instance for $theta=0.5$, we had $4$, so this time we can increase the $n$ and get closer to $theta=0.5$. My question is can this be done.
No - the key intuition of QPE is that $e^{2 pi i theta} $ holds for $theta in [0, 1) $, and the reading out the ancilla provides the binary representation of the fraction.
If you changed the operator to $e^{2 e i theta}$, $theta not in [0, 1)$ necessarily. Instead, you should just use the typical QPE approach, but then find $zeta$ where $2 e i zeta = 2 pi i theta implies zeta = frac{pi}{e}theta$, and correct for symmetries afterwards.
Correct answer by C. Kang on May 3, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP