Missing numbers inside square

In the first column all numbers are multiples of 5. In the last column all numbers are multiples of 7. By addition and subtraction we obtain (63 + 70 + 56) - (60 + 55 + 65) = 3^2. In the second column and the fifth column, all numbers are multiples of 10 plus one prime. By addition and subtraction we obtain (800 + 80 + 200 + 40 +3) - (160 + 13 + 400 + 20 + 430) = 10^2. In the third column and the fourth column all numbers are multiples of 5. By addition and subtraction we obtain (55 + 90 + 985) - (1065 + 30 + 10) = 5^2. So the missing numbers are 55, 1065, 13, 56 (shown outside the square).

The numbers could be

Explanation

May be answers are :

Reason: