TransWikia.com

Why the transition of electron from an excited state to metastable state in a lasing medium is radiation less?

Physics Asked on July 1, 2021

When an electron transitions from an excited state to the metastable state, no radiation is emitted i.e. a radiationless transition.

My question is: Where does the energy difference between excited state and metastable state go?

One Answer

It depends, there are different decay processes happening in a medium. Not all the decays are radiative (i.e., with emission of a photon). Moreover, regarding photonic channel decay, non-induced transition provoke isotropic photon emission. In lasing you care about spontaneous emission over the cavity direction. Being the fraction of spontaneous emitted photons over the cavity direction negligible, and also considering non resonant photons (usually the transition to metastable states is done with non-resonant photons with the cavity...), these decays do not produce lasing effects.

Answered by SoterX on July 1, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP