Physics Asked on July 1, 2021
When an electron transitions from an excited state to the metastable state, no radiation is emitted i.e. a radiationless transition.
My question is: Where does the energy difference between excited state and metastable state go?
It depends, there are different decay processes happening in a medium. Not all the decays are radiative (i.e., with emission of a photon). Moreover, regarding photonic channel decay, non-induced transition provoke isotropic photon emission. In lasing you care about spontaneous emission over the cavity direction. Being the fraction of spontaneous emitted photons over the cavity direction negligible, and also considering non resonant photons (usually the transition to metastable states is done with non-resonant photons with the cavity...), these decays do not produce lasing effects.
Answered by SoterX on July 1, 2021
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