Physics Asked on March 18, 2021
I get that $(1 – Omega) = Omega_k$.
What I used to know, but have forgotten and cannot find is
what is the equation relating $R_{curv}$ (radius of curvature) and $Omega_k$?
I have found the answer to this question before, but now that I want to work with it again, I seem to have misplaced it, and I am unable to find it. What I remember be is that
$R_{curv}$ = A $sqrt {frac {-1} {Omega_k}}$,
where A is the coefficient whose value I would like to know in units of meters.
ADDED
I found the answer in
https://arxiv.org/abs/1911.02087
page 2. The answer is A = c/$H_0$.
The value given for the curvature density is $Omega_k$~-0.1.
The value given for the radius of curvature is $R_{curv}$~10Gpc~33Gly.
Note that if $Omega_k$>0, the value of $R_{curv}$ is imaginary.
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