Physics Asked by Aditya Kumar on May 23, 2021
I have a question on fluid dynamics which requires to find the derivative of velocity wrt to height? It was solved by my teacher but I am not able to grasp the solution.
Here is the question: –
A tank is filled with water upto a height h. The top of the tank has an area of cross section A. Water is coming out through a circular hole of area A/3. Find the initial acceleration with which the top level of water is decreasing?
Can someone explain the part where derivative is taken and velocity changes into acceleration.
v1=dh/dt, Hence, v1*(dv1/dh) =(dh/dt) *(dv1/dh) =dv1/dt =d^2(h)/dt^2=acceleration, This is how we end up with acceleration term a.
Answered by Chaitanya Tarkunde on May 23, 2021
$a=dv/dt$
$a=(dv/dh)times( dh/dt)$ (Multiply and divide by dh or to say using chain rule)
$a=v(dv/dh)$
Answered by Danny LeBeau on May 23, 2021
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