Physics Asked by BrazyOski on January 7, 2021
We are asked to find the all the states in the system given by two identical fermions on a circle only in terms of the Grassmann formalism. Furthermore, we have to show that $lim_{n to infty} N(E)/E = mL^2/4pihbar^2$ such that $N(E)$ is the number of eigenstates such that their energy does not exceed $E$.
As a hint we are given that we let $psi(zeta)=sum zeta_i psi_i$.
Any help is appreciated!
Attempted Solution:
$$
zeta_1zeta_2(e^{ix_1}e^{2ix_2} pm zeta_1zeta_2(e^{2ix_1}e^{ix_2})
$$
$$
zeta_2zeta_1(e^{2ix_1}e^{ix_2} pm zeta_2zeta_1(e^{ix_1}e^{2ix_2})
$$
Can anyone check my work?
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