Physics Asked on July 2, 2021
Photons move on null geodesics and the equation of motion on equatorial plane after some algebra can be written as
$$e^{nu}dot{t}^2-e^{-nu}dot{r}^2-r^2dot{phi}^2 = 0$$
$phi =0$ for the radial motion thus above equation becomes
$$e^{nu}dot{t}^2-e^{-nu}dot{r}^2 = 0$$
from where one can write down
$$frac{d r}{d t} = pm Big(1-frac{2M}{r}Big)$$
and integration will lead to
$$t = r +2MlnBig|1-frac{r}{2M}Big|+C hspace{12.5mm} And hspace{12.5mm} t = -r -2MlnBig|1-frac{r}{2M}Big|+C$$
Here I’m not sure what kind of physical meaning I should attribute to the final equations. I see at $r=2M$, $tto mpinfty$ but this also confuses my interpretation.
The physical meaning is that for a distant observer at fixed $r$, for whom $dt$ approximately represent a proper time interval, ingoing light appears to take an infinitely long time to reach the event horizon.
The other solution is for outgoing light and tells you that light emitted from sources at fixed $r$ takes an increasingly long time to reach a distant observer, with an asymptote to an infinitely long time at the event horizon (where a fixed source cannot exist). This is of course the phenomenon of gravitational time dilation.
Correct answer by ProfRob on July 2, 2021
Those time coordinates represent the incoming and outgoing photons in the spacetime diagram. At the limit $R=2M$, the coordinate time $tto infty$ (equivalent to saying it crosses the horizon).
Answered by Monopole on July 2, 2021
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