Physics Asked on April 4, 2021
In QM textbooks the single step potential problem is explained in great detail. However, it is hard to understand what happens when $V_{0}<0$. Could anyone please explain qualitatively, how the incident wave, transmitted wave, and the reflected wave behave?
$V(x) = 0 (x > 0)$
$V(x) = V_{0}, V_{0}<0, (x le 0)$
The zero of potential can be shifted up and down arbitrarily. What matters is the difference E-V, where E is the kinetic energy of the particle. The solution is the same.
Answered by Ganapati Natarajan on April 4, 2021
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