Physics Asked on June 18, 2021
I have been attempting to solve the following problem (my question is at the very bottom of this post)
And here is the answer for the first part
Question: Why is the reaction force $R$ not equal to $mgsin theta$? (I would think this is the case by Newton’s Third Law, however, something is wrong with this logic.)
I think you mean to say $mgcostheta$ and not $sin theta$. See below (note I only display the force of gravity):
The way we usually get that $R=mgcostheta$ is by realizing that the forces perpendicular to the incline are balanced on the block. So we have $Sigma F_perp = R-mgcostheta=0implies R=mgcostheta$.
However, this is only true when the wedge is not moving. Because the wedge is moving, $Sigma F_perp neq 0$ so you can't conclude that $R=mgcostheta$.
Correct answer by user256872 on June 18, 2021
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