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Knowing the wavefunction $Psi(x,y,z,0)$ is enough to know the functions for $frac{partial^2Psi(x,y,z,0)}{partial{x^2}}$, $frac{partial^2Psi(x,y,z,0)}{partial{y^2}}$, $frac{partial^2Psi(x,y,z,0)}{partial{z^2}}$, seeing as how they are second derivatives of the wavefunction with respect...
Asked on 11/29/2020 by Anders Gustafson
2 answerMagnetic fields are created due to electron spin in the magnet. But how exactly does an electron "spinning" create forces around the magnet? Also, the magnetic force on a charge...
Asked on 11/29/2020 by carbenoid
2 answerIs there a method to "decompress" the acceleration scalar? For example, I am computing the scalar as:$sqrt{a_x^2 + a_y^2 + a_z^2}$where $a_x, a_y$ and $a_z$...
Asked on 11/29/2020 by GK89
1 answerInspired by this answer, I want to ask what is going to limit the speed of the tip of a whip in a vacuum? From my understanding, on Earth...
Asked on 11/29/2020 by Nick The Dick
0 answerWhy does the Hartree-Fock method for electronic structure work so well for atoms? More specifically, why is the "correlation energy" a relatively small component of an atom's (ground state) energy?...
Asked on 11/29/2020 by creillyucla
1 answerI'm studying the geocentric Ptolemaic model of an upper Planet. My goal is an expression of the (squared) distance of $h$ from the planet to Earth, depending on the...
Asked on 11/29/2020 by Joe_base
0 answerI've been reading Lancaster & Blundell, and in Chapter 14 they focus on the Lagrangian$$mathcal{L}=(partial^mupsi)^dagger(partial_mupsi) - m^2psi^daggerpsi.$$To impose invariance to the transformation $psirightarrowpsiexp(ialpha(x))$, where...
Asked on 11/29/2020 by dsfkgjn
2 answerI am currently trying to brush up on my skills in dimensional analysis, and computing with units. Is there a good source of worked examples, and exercises with solutions? I'd...
Asked on 11/29/2020 by harlekin
1 answerIn the action where the Ricci curvature couples with the field $B^{mu}$: $$S=int d^4xsqrt{-g}left(-frac14F_{munu}F^{munu}+V(B_{sigma}B^{sigma}) +Rlambda B_{mu}B^{mu}right)$$ To obtain the equations for the field $B^{mu}$ I did the...
Asked on 11/29/2020 by MicrosoftBruh
2 answerHow is C defined in terms fo frequency? So the power gain of a resonator ring is : $$text{Power Gain}=frac{C^2}{|1-Tsqrt{1-C^2}|^2}$$ $C =$ coupling factor,$T =$ attenuation....
Asked on 11/29/2020 by futball11
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