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In the section on Coulomb's law in QFT by Schwartz, he expands $-frac{1}{4}F_{munu}^{2}$ to get $-frac{1}{2}(partial_{mu}A_{nu})^{2} + frac{1}{2}(partial_{mu}A_{mu})^{2}$, can someone please explain how he arrives at the second...
Asked on 06/14/2021 by aphy11
0 answerMy question boils down to how the Fourier transform is discretized when we discretize the field $phi(x)$ in a Lagrangian $mathcal{L}$. To put things on a concrete footing,...
Asked on 06/14/2021
1 answerConsider a pipe with length $L$ and uniform radius $A$ is held vertically. According to the continuity equation, the velocity of water going into the pipe seems to be the...
Asked on 06/14/2021
6 answerI asked this on the Electronics Stack Exchange and someone suggested for me to ask it here too. https://electronics.stackexchange.com/q/542983 Studying basic direct current circuits, I've come across the term...
Asked on 06/14/2021
0 answerI'm part of the robotics team at my school, and we built a robot for the competition. To prevent static discharge from the chassis to the circuit, we attached a...
Asked on 06/14/2021
3 answerIf you imagine light source passing through a single slit of variable thickness, as you lower the thickness of the slit the light will diffract more and more until the...
Asked on 06/14/2021
2 answerOne of the things I learned from Heisenberg's Uncertainty Principle is that when you try to observe the position of a microscopic particle, you have to use a light of...
Asked on 06/14/2021
2 answerToday I had my body scanned by a GE Lunar Prodigy densitometer installed in a small RV of a company that tours California offering body composition scans...
Asked on 06/14/2021
2 answer$$nablatimes overrightarrow{E} = -frac{doverrightarrow{B}}{dt} $$Faraday's Law says: any change in the magnetic field causes circulation of electric field. $$mathbf{nabla times B} = mu_0 mathbf{j} + frac{1}{c^2}frac{partial mathbf{E}}{partial t}$$Maxwell's...
Asked on 06/14/2021 by user50322
2 answerThis is an intensisity vs. wavelength graph of X-ray emmision. The cut-off wavelength is the minimum wavelength of the X-ray emitted....
Asked on 06/14/2021
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