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Meaning and application of the connection coefficients (Christoffel symbols)

Physics Asked by Luca M on June 27, 2021

I know that in polar coordinates, it is
$frac{partial ,{{mathbf{e}}_{r}}}{partial theta }={{mathbf{e}}_{theta }}$ and $frac{partial ,{{mathbf{e}}_{theta }}}{partial theta }=-{{mathbf{e}}_{r}}$
where ${{mathbf{e}}_{r}}$ and ${{mathbf{e}}_{theta }}$ are the basis unit vectors.

Anyway, using the definition of the connection coefficients (Christoffel symbols) it should also be

$frac{partial ,{{mathbf{e}}_{r}}}{partial theta }={{Gamma }^{r}}_{rtheta },{{mathbf{e}}_{r}}+{{Gamma }^{theta }}_{r,theta },{{mathbf{e}}_{theta }}$ and
$frac{partial ,{{mathbf{e}}_{theta }}}{partial theta }={{Gamma }^{r}}_{theta ,theta },{{mathbf{e}}_{r}}+{{Gamma }^{theta }}_{theta ,theta },{{mathbf{e}}_{theta }}$

And since it is ${{Gamma }^{r}}_{theta ,theta }=-r$ , ${{Gamma }^{theta }}_{r,theta }=frac{1}{r}$ , ${{Gamma }^{r}}_{r,theta }=0$, ${{Gamma }^{theta }}_{theta ,theta }=0$ (calculated with the metric)
it should be

$frac{partial ,{{mathbf{e}}_{r}}}{partial theta }=frac{1}{r}{{mathbf{e}}_{theta }}$ and $frac{partial ,{{mathbf{e}}_{theta }}}{partial theta }=-r,{{mathbf{e}}_{r}}$

Where am I wrong?

One Answer

You are using two different sets of basis vectors. $frac{partialmathbf e_r}{partial theta} = mathbf e_theta$ and $frac{partial mathbf e_theta}{partial theta} = -mathbf e_r$ hold for the orthonormal polar basis, in which the metric takes the form

$$g_{ij} = pmatrix{1 & 0 0 & 1}$$

The connection coefficients you quote arise from the polar coordinate basis $left{frac{partial}{partial r},frac{partial}{partial theta}right}$ which is not orthonormal, and in which the metric takes the form

$$g_{ij} = pmatrix{1 & 0 0 & r^2}$$

The two bases are related via $mathbf e_r = frac{partial}{partial r}$ and $mathbf e_theta = rfrac{partial }{partial theta}$.


An important thing to recognize is that the basis $left{frac{partial}{partial r},frac{partial}{partial theta}right}$ arises naturally as the basis induced by the polar coordinates $(r,theta)$. On the other hand, the orthonormal basis ${e_r,e_theta}$ is not induced by a coordinate system; there is no set of coordinates $(u,v)$ such that $e_r = frac{partial}{partial u}$ and $e_theta =frac{partial}{partial v}$. This is an example of a non-holonomic basis.

The reason that this is important is that in your first pass through GR, you will likely start off by using holonomic bases exclusively. Accidentally using a non-holonomic basis can lead to some apparent contradictions.

Correct answer by J. Murray on June 27, 2021

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