TransWikia.com

Interpretation of the vector current in field theory

Physics Asked on January 2, 2021

In field theory we write

$$J^mu=bar{Psi}gamma^muPsi$$

But I can’t understand why it is so. Could anyone explain each of the terms in the multiplication?

One Answer

Well, such form follows from the Noether theorem, which states that if action (in Minkowski space-time) $$ S = int d^{4}xL $$ of fermions $Psi$ is invariant under transformation $$ tag 1 Psi to e^{ialpha}Psi , quad bar{Psi} to e^{-ialpha}bar{Psi}, $$ then exists the object $J$ with one vector indice, namely $$ tag 2 J_{mu} = ifrac{partial L}{partial (partial^{mu}Psi)}alpha Psi - ialpha bar{Psi}frac{partial L}{partial (partial^{mu}bar{Psi})}, $$ which is conserved: $$ partial_{mu}J^{mu} = 0 $$ Conservation law can be rewritten in the form $$ frac{d}{dt}int_{Omega} d^{3}mathbf r J^{0} equiv frac{dQ}{dt} = -int_{dOmega} dmathbf {S}cdot mathbf J, $$ which means that the changing with time the quantity $int J^{0}d^{3}mathbf r$ in the given volume $Omega$ is related to the flux of quantity $mathbf J$ through surface $dOmega$.

The scalar quantity $Q$ is thus called charge (with $J^{0}$ being charge density), while the quantity $mathbf J$ is current density.

The vector nature of $J^{mu}$ follows from the fact that the transformation $(1)$ isn't related to space-time transfrormations, while indices are. So the only quantity which can be $J$ in our case is the vector (one indice comes from expilcit expression for Noether current).

As for explicit form of current $J^{mu}$, let's use particular lagrangian of free fermions, $$ L = bar{Psi}(igamma^{mu}partial_{mu} - m)Psi , $$ with $gamma_{mu}$ being Dirac matrices, $Psi$ being Dirac spinor, $bar{Psi} equiv Psi^{dagger}gamma^{0}$ being Dirac conjugated spinor. Such lagrangian is constructed from the requirement of Lorentz invariance and from requirement that we obtain Dirac equation for field with spin $frac{1}{2}$ after using Euler-Lagrange equations.

and insert it into $(2)$. You'll immediately obtain the result (up to the sign, which isn't relevant here).

Answered by Name YYY on January 2, 2021

Add your own answers!

Ask a Question

Get help from others!

© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP