Physics Asked by Andrea Maiani on February 2, 2021
Following “Introduction to Fourier Optics” by Goodman, in section 5.3 it is explained how to derive the impulse response of a lens.
Where $(u,v)$ are the coordinates of the output plane while $(xi, eta)$ are the coordinates of the input plane.
I don’t understand how to apply convolution to this impulse response function as it depends also on the input coordinates.
I would have expected a function like $h(u,v)$ in order to obtain the final image like:
$$
U_f(u,v)=h(u,v)*U_i(u,v) = int h(u-u’,v-v’)U_i(u’,v’) du’dv’
$$
How should I interpret the convolution operator?
In the book this function is maybe improperly called "impulse response" because as I said it depends on the coordinates of the input image. The real impulse response of the lens, also called Point Spread Function, is derived in subsequently and is: $$ h(x,y) = iint_{-infty}^{+infty} P(lambda z_2 x', lambda z_2 y')exp[-j2pi (x x'+yy')]dx'dy' $$
Answered by Andrea Maiani on February 2, 2021
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