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Interface boundary conditions of superconductor

Physics Asked by ECA18 on May 7, 2021

Are the usual interface conditions for electromagnetic fields, i.e.
$$mathbf{n}_{12}times(mathbf{E}_1-mathbf{E}_2) = 0,$$
$$mathbf{n}_{12}bullet(mathbf{D}_1-mathbf{D}_2) = sigma_s,$$
$$mathbf{n}_{12}bullet(mathbf{B}_1-mathbf{B}_2) = 0,$$
$$mathbf{n}_{12}times(mathbf{H}_1-mathbf{H}_2) = mathbf{J}_s, $$
valid at the interface if one of the media is a superconductor? I would assume that they are since they are derived from Maxwell’s equations. Is this correct?

One Answer

Magnetic field is expelled from a superconductor by the Meissner effect, so the normal magnetic field goes to zero at the surface. For a type-I superconductor, a strong enough magnetic field will destroy the superconducting state. In a type-II superconductor a partial magnetic field can penetrate.

Answered by amateurAstro on May 7, 2021

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