Physics Asked on March 31, 2021
While studying the book Heat and Thermodynamics by Zemansky and RH Dittman, in the topic ‘equation for a hydrostatic system’ (page no. 88) it was given
in equation 4.12, when we take Pressure P constant, how the dv/dt (marked in red sqaure) got converted into partial derivative? (marked in red square)
Write $$dV=left(frac{partial V}{partial P}right)_TdP+left(frac{partial V}{partial T}right)_PdT,$$ then $$frac{dV}{dT}=left(frac{partial V}{partial P}right)_Tfrac{dP}{dT}+left(frac{partial V}{partial T}right)_P.$$ If the pressure is constant $dP=0$, and the first term drops out $$frac{dV}{dT}=left(frac{partial V}{partial T}right)_P.$$
Correct answer by Urb on March 31, 2021
Get help from others!
Recent Answers
Recent Questions
© 2024 TransWikia.com. All rights reserved. Sites we Love: PCI Database, UKBizDB, Menu Kuliner, Sharing RPP