How the electrostatic energy of attraction is minimum in the ground state of an atom?

Question

In the definition of the ground state of an atom, it is given that

The ground state is one in which the electrostatic energy of
attraction is minimum. This state is called the ground state of the
atom.

But, when the atom is in its ground state then the electron and the nucleus will be closest as compared to when they are in the excited state. Isn't it?
Then, the electrostatic force of attraction should be maximum as it is proportional to 1/r^2.
How is it a minimum? What am I missing?

Tony Stark · Accepted Answer

Yes your thinking is correct and the electrostatic force of attraction is maximum in ground state. But that does not change the fact that electrostatic energy is minimum.

Consider this analogy:
Suppose you drop a ball from a height.It will reach the ground - its most stable state. In the ground state,its Potential Energy is minimum and the force of attraction is maximum.

Get it?
You are misinterpreting energy for force here.
Further, in general, any system has a tendency to attain least potential which is its most stable state.

P.S. If you still have any doubt,comment below.

G. Smith · Answer

What you are missing is that the electrostatic potential energy between the nucleus and the electrons is negative. “Minimum” here means “as negative as possible”.
For example, for hydrogen the electrostatic PE in the ground state is -27.2 eV. In the first excited state it is -6.8 eV.

How the electrostatic energy of attraction is minimum in the ground state of an atom?

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