How many forces are acting on a projectile when it is passing through the highest point in the trajectory if air resistance is ignored?

Forces describe the change of velocity (or momentum, technically speaking) of an object. Not the current velocity, just the change. If the velocity towards east doesn't change (= is constant), then there can't be any net force applied to the object in that direction. The direction in which velocity changes is the vertical one, so the net force applied to the projectile must be in that direction as well, and gravity is fully sufficient to describe this vertical force.

The object is moving towards the east with a constant velocity at all points of its trajectory and this is not due to a force acting on it but due to no force acting on it in that direction (ignoring air resistance).

Let me clarify.

You projected the object which was at rest earlier with some velocity at $45°$ . This means you applied a force to throw the object but the moment the object left the contact with your hand, there is no force acting on it except the downward gravity and because of this force of gravity , the vertical component of the velocity given changes but since there is nothing to apply a force on the object in the horizontal direction , it's velocity in that direction doesn't change.

So we don't need to apply force to move a body with constant velocity.

There was a similar confusion with Aristotle who said that we need to apply a force to a body to make it move constantly . But Galileo then said that we don't need to apply a force to a body to move it constantly but a force is needed if we want to change the state of the body i.e. to make it move from rest or change the velocity with which it was moving earlier.

Hope it helps ?.

The only force acting on the particle thoughout its trajectory is gravity.