Physics Asked by Johan Hansen on January 10, 2021
So I have a very complicated Hamiltonian given by:
$$ H_R(psi, P_psi) = frac{-B_0 R^3}{2 pi} (2 psi – sin(2 psi) + sqrt{B_0^6 R^6 V(psi)^2 – P_psi^2} $$
where
$$V(psi) = frac{1}{pi} sqrt{b_0^4 sin^4(psi) + (pi P/M – psi + frac{1}{2}sin(2psi))^2}.$$
The potential makes this Hamiltonian VERY hard (according to me) to evaluate. My goal is to get the equation of motion on form $psi(R)=$ something, for arbitrary $P/M$. $B_0$ and $b_0$ are just some constants.
In principle I could start from
$$ frac{partial H_R(psi, P_psi)}{partial P_psi} = partial_R psi equiv dot{psi}.$$
Then I would get
$$ dot{psi} = frac{-P_psi}{sqrt{B_0^2 R^6 V(psi)^2 – P_psi}}. $$
Then I could integrate $psi(R)$ w.r.t $R$. But I don’t know the limits of this integral. And even if I did, it would be a next to impossible task to integrate? Not even Mathematica can handle that integral.
So I will have to make some approximations I guess.
I could in principle solve it numerically but I want a solution for arbitrary $P/M$.
Any input on how I can ultimately get the equation of motion on form $psi(R) = $ something?
I am grateful for any help.
$P_{psi}$ is canonical momenta in $psi$ which is the polar angle spanning a 3-sphere. P and M is the momentum and mass of a D-brane or graviton. The range of $psi$ is $[0, 2 pi]$
from the Hamiltonian :
$$H=H(psi,P_psi)$$
you get two first order differential equations :
$$dot{P}_psi=-frac{partial H}{partial psi}=f_1(P_psi,,psi)tag 1$$ $$dot{psi}=frac{partial H}{partial P_psi}=f_2(P_psi,,psi)tag 2$$
if you linearized Eq. (1) and (2), you obtain analytical solution.
$$begin{bmatrix} Delta{dot P}_psi Delta{dot{psi}} end{bmatrix}=left[ begin {array}{cc} {frac {partial }{partial P_{{psi}}}}f_{ {1}} left( P_{{psi}},psi right) &{frac {partial }{partial psi} }f_{{1}} left( P_{{psi}},psi right) {frac { partial }{partial P_{{psi}}}}f_{{2}} left( P_{{psi}},psi right) &{frac {partial }{partial psi}}f_{{2}} left( P_{{psi}}, psi right) end {array} right]_{[P_psi=P_{psi_0},psi=psi_0]} ,begin{bmatrix} Delta{ P}_psi Delta{{psi}} end{bmatrix}$$
Answered by Eli on January 10, 2021
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