Physics Asked on August 14, 2021
Suppose I have a coordinate system, call it $S$, in which an observer $O$ is not moving, and $O’$ is moving with constant velocity and another coordinate system $S’$ where $O’$ is not moving and $O$ is moving in a constant velocity, they both have a stop watch and measure the time of the movement of $O’$, what time does each measure?
Since in $S$, $O$ is not moving then he measures the time of $O$ by using the Minkowsky metric, when I change to $S’$ then $O’$ is not moving and he measures time by using a different metric, that is the metric I get after I change coordinates using the Lorrentz transformation.
My question is this idea correct, have I misunderstood something? If yes can you explain what is my mistake?
Should be correct, except in special relativity people use the term "frame" rather than "metric", which is used more often in general relativity. You can say $u$ boosted from frame $S$ to frame $S'$ with a Lorentz boost.
Answered by user9316828 on August 14, 2021
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