Physics Asked by user37420 on January 26, 2021
A point charge of magnitude $Q$ is placed inside a conducting cylinder of length $L$ and radius $R$ at its centre. What is the flux through the cylinder?
I know that I have to use Gauss Law here but my concern is:
Since it is a conducting cylinder, there would be equal and opposite charges induced on its surface. How do I account for these charges?
Help would be appreciated.
Remember I'm not 100% sure about my answer.
If you consider the gaussian surface just above the surface of the cylinder then the total charge enclosed by your gaussian surface will be Q+ Q (induced)-Q (induced) = Q. So the flux will be Q/€°. If you consider the gaussian surface in between the outer and inner surfaces of the cylinder (provided the surface of the cylinder is a bit thick) then the total charge enclosed by your gaussian surface will be Q~Q = 0. Therefore the flux is zero. I'm not a teacher, I'm a student of 16 year old. If I've made a mistake forgive me. Thank you for making me to think a bit.
Answered by Akshay Nagraj on January 26, 2021
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