Event horizon vs high gravitational field: How is it light can escape a gravity greater than the speed of light

Gravity "$g$" has units of ms$^{-2}$. You cannot compare this with the speed of light that has units of ms$^{-1}$

You are supposed to calculate the escape velocity at the event horizon, which will (just by chance) come the same if you consider Newtonian gravity or general relativity. For the Scwarzschild metric, the escape velocity comes out to be $c$, and even if you consider the escape velocity due to Newtonian gravity, it will come out to be $c$.

As a non-physicist, I think this would be sufficient, but if you are interested, you should try to learn both, Newtonian gravity, and General Relativity, then you might get a clearer picture.

What I gather since posting my question is that gravity at the event horizon of a super massive black hole (BH) can be vastly less than that at the event horizon of a small primordial black hole (PBH) and yet still light cannot escape. The reason for this is that the event horizon is the point at which the curvature of space induced by the BH curves back upon itself - think of water emptying via a drain in our dimension; it spins about the drain in a descending vortex starting at a boundary where the water is captured in such a curve, curving back upon itself as it courses down into the drain. In the case of the PBH, the curve of spacetime is so sharp as to create a commensurately high gravity; but it is the curvature of spacetime that is capturing the light and all else. The supermassive BH generates a vastly broader distortion of spacetime with a much greater radius and thus a much more gentle curvature at the point where it curves back upon itself resulting in a commensurately lower gravity at the surface of its event horizon. Hence it is the point where the curvature of space has curved back upon itself that is inescapable, not gravity.