Physics Asked by François Ritter on April 11, 2021
I apologize to ask, again and again, a question that seems to come back often, but I believe this is new.
I am trying to test the equivalence principle applied to two similar situations:
$dtau’ = frac{dt}{sqrt{1+(frac{alpha t}{c})^2}}$
I just wanted to make sure this is true for $Lneq0$.
Can you help me ? Please do not use $c=1$, or $G=1$. Do we agree that, in the situation 2), Bob feels a proper acceleration of
$alpha = frac{1}{sqrt{1-frac{r}{r_{s}}}}frac{GM}{r^2}$
Using the popular convention?
Thank you !
In the first problem, Bob's position relative to Alice and/or relative to $x=0$ is irrelevant, since only velocity and acceleration figure into the calculation. You need to specify that Bob is at rest at $t=0$. With that additional assumption, that formula is correct.
In the second problem, Bob's proper acceleration is correct, but it isn't clear what the $(x,t)$ coordinates are supposed to be. You can't just put inertial coordinates on this spacetime, since it isn't flat. You could try to find "approximately inertial" local coordinates, but they would be either inexact or very ugly. You could also calculate quantities actually measurable by Alice, such as Bob's apparent Doppler shift and angular size as a function of Alice's proper time, and compare them to the same quantities calculated in the special relativistic problem, which would be easier but tedious. Either way the results would be similar to the special-relativistic case but not identical since there is spacetime curvature.
Correct answer by benrg on April 11, 2021
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