Energy conservation equation for an object rolling up an incline

An sphere of radius $R$ rolls up an incline. We can write mechanical energy conservation equations for this motion because neither does the normal or the frictional force do any work.

At the top of the incline the kinetic energy of this object will be zero and thus all of the mechanical energy will be In the potential form.

Assuming zero of potential $R$ above the horizontal,hence
$U_i=0$ where $U_i$ is the potential when the object is rolling on a horizontal plane.

At the top of the incline the potential energy of the object is $U_f=m g (h+ R cos theta-R)$.

When I compare this with other places on the internet I find that my equation is wrong.
They don’t take into account the term

$R cos theta=h’$.
Why is this so. Am I wrong? Isn’t this the way, we can write the energy equations?

(Links where they ignore this term:
https://www.google.com/search?client=ms-android-vivo&sxsrf=ALeKk03huUks-ybuFPC8eKFe6kuoXJme7Q%3A1610098556804&ei=fCf4X-zIMNGW4-EPsr6poAI&q=to+what+height+will+a+sphere+roll+up+an+incline&oq=to+what+height+will+a+sphere+roll+up+an+incline&gs_lcp=ChNtb2JpbGUtZ3dzLXdpei1zZXJwEAM6BAgAEEc6BAgjECc6BwghEAoQoAFQmZwRWJbGEWDsyhFoAHABeAGAAccCiAGlFJIBBTItOS4xmAEAoAEByAEIwAEB&sclient=mobile-gws-wiz-serp#

https://www.concepts-of-physics.com/mechanics/rolling-without-slipping-of-rings-cylinders-and-spheres.php