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Does the FLRW metric account for the decrease in density for an expanding universe?

Physics Asked on July 9, 2021

In other words, is it assumed that the fluid density is constant after expansion and through the time development of an expanding universe?

One Answer

For what I remember I would say that FRW metric certainly account for that; in fact a constant energy density in an expanding universe should mean that there is energy production, but from where exactly? I can cite the Hubble parameter equation begin{equation*} left(H(t)right)^2 = left(H(t_r)right)^2 left( frac{Omega_{text{mat}}(t_r)}{s^3(t,t_r)} +frac{Omega_{text{rad}}(t_r)}{s^4(t,t_r)} +Omega_Lambda(t_r) +frac{Omega_alpha(t_r)}{s^2(t,t_r)} right) end{equation*} where you have an emission time $t$, a receiving time $t_r$ and a normalized scale factor $s(t,t_r)doteqtilde{S}(t)/tilde{S}(t_r)$ (where $tilde{S}$ represents $S/sqrt{|K|}$). You can recognize the presence of

  • Matter density parameter, decreasing with $s^3$, representing exactly the tridimensional volume change
  • Radiation density parameter, that goes with $s^4$, why? because the expansion redshifts the radiation!
  • Vacuum density parameter, just constant because the vacuum has an unaltered nature
  • Curvature density parameter, a really esotic and wild animal!

Considering also that $H(t)approxpartial_t tilde{S}(t)/tilde{S}(t)$ this means that the universe expands changing scale factor due to the fact that energy density changes.

I hope it was helpful and without big errors.

Answered by Rob Tan on July 9, 2021

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